The Sun's angular diameter is measured to be 1920". The distance D of the sun from the earth is 1.496 $\times 10^{11}$ m. So find the diameter of the Sun.

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Solution

We know that $1^{''} = (\frac{1}{3600}) \times \frac{π}{180} r a d$
Angular diameter $θ = 1920^{''} = 1920 \times \frac{π}{3600 \times 180} r a d = 0.0093 r a d$
Diameter $d = θ r = 0.0093 \times 1.496 \times 10^{11} m = 1.39 \times 10^{9} m$

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