The temperatures of two bodies measured by a thermometer are t-1 - 20- C - 0-5- C and t-2 - 50- C-0-5- C- The temperature difference and the error therein is-70- C - 0-5- C30- C - 1- C30- C - 0-5- C70- C - 1- C

The correct option is B 30^∘ C ± 1^∘ CHere, t_1=20^∘ C ± 0.5^∘ C t_2=50^∘ C ± 0.5^∘ C The temperature difference of two bodies is t = t_2 t_1 = 50^∘ C 20 ...

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Standard XII

Physics

Finding Average Velocity

The temperatu...

Question

The temperatures of two bodies measured by a thermometer are $t_{1} = 20^{\circ} C \pm {0.5}^{\circ} C$ and $t_{2} = 50^{\circ} C \pm {0.5}^{\circ} C$ . The temperature difference and the error therein is:

30^{\circ} C \pm 1^{\circ} C

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70^{\circ} C \pm {0.5}^{\circ} C

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30^{\circ} C \pm {0.5}^{\circ} C

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70^{\circ} C \pm 1^{\circ} C

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Solution

The correct option is A $30^{\circ} C \pm 1^{\circ} C$
Here,
$t_{1} = 20^{\circ} C \pm {0.5}^{\circ} C$
$t_{2} = 50^{\circ} C \pm {0.5}^{\circ} C$
The temperature difference of two bodies is
$t = t_{2} - t_{1} = 50^{\circ} C - 20^{\circ} C = 30^{\circ} C$
The error in temperature difference is given by
$Δ t = (Δ t_{1} + Δ t_{2})$
$= ({0.5}^{\circ} C + {0.5}^{\circ} C) = 1^{\circ} C$
$∴$ The temperature difference is $30^{\circ} C \pm 1^{\circ} C$ .

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The temperatures of two bodies measured by a thermometer are t1=20∘C±0.5∘C and t2=50∘C±0.5∘C. The temperature difference and the error therein is:

The correct option is A 30∘C±1∘CHere, t1=20∘C±0.5∘C t2=50∘C±0.5∘C The temperature difference of two bodies is t=t2−t1=50∘C−20∘C=30∘C The error in temperature difference is given by Δt=(Δt1+Δt2) =(0.5∘C+0.5∘C)=1∘C ∴ The temperature difference is 30∘C±1∘C.

The temperatures of two bodies measured by a thermometer are $t_{1} = 20^{\circ} C \pm {0.5}^{\circ} C$ and $t_{2} = 50^{\circ} C \pm {0.5}^{\circ} C$ . The temperature difference and the error therein is: