The time of flight of projectile is $10$ second and its range is $500m$. The maximum height reached by will be $(g=10m/s^2)$

The correct option is D $125m$
Given,

$T=10sec$

$R=500m$

$g=10m/s^2$

Maximum height, $H=\frac{u^{2}si{n}^2\theta }{2g}$.. . . . . . . . . . . . . .(1)

Time of flight, $T=\frac{2usin\theta }{g}$

$10=\frac{2usin\theta }{10}$

$usin\theta =50$

From equation (1),

$H=\frac{50\times 50}{2\times 10}$

$H=125m$

The correct option is D.