The total number of moles of water present in $96 g$ of water is

16.23 m o l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.23 m o l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8.23 m o l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.33 m o l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $5.33 m o l$
$1$ mole of water weighs $= 18 g$
x mole of water weighs $= 18 g \times x = 96 g$
or $x = \frac{96}{18} = 5.33 m o l$

Suggest Corrections

Similar questions

720

90

Total number of neutrons present in five moles of water molecules is:

Join BYJU'S Learning Program