The value of -2-3-3-2-1-3 -0 is 0-True-False-

The correct option is B False Given, [2^3 3^2 1^3 ]^0 Now, (2^3 3^2 1^3)^0 = (8 9 1)^0 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; n ...

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Zero Exponent

The value of ...

Question

The value of $[2^{3} - 3^{2} - 1^{3}]^{0}$ is 0.

True

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False

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Solution

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Similar questions

x^{2} + k (4 x + k - 1) + 2 = 0

- \frac{2}{3}, 1

\frac{2}{3}, - 1

\frac{3}{2}, \frac{1}{3}

- \frac{3}{2}, - \frac{1}{3}

k x^{2} + 2 x + 3 x = 0

\frac{1}{3}

\frac{- 1}{3}

\frac{2}{3}

\frac{- 2}{3}

The value of $[2^{3} - 3^{2} - 1^{3}]^{0}$ is 0.

32 . T h e m i n i m u m v a l u e o f t h e e x p r e s s i o n 3 s e c^{2} x - 4 s e c x + 1 i s (A) - \frac{1}{3} (B) \frac{1}{3} (C) \frac{2}{3} (D) 0

\frac{3 \times 1^{3}}{1^{2}} + \frac{5 \times (1^{3} + 2^{3})}{1^{2} + 2^{2}} + \frac{7 \times (1^{3} + 2^{3} + 3^{3})}{1^{2} + 2^{2} + 3^{2}} + \dots upto 10 terms

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