The value of $\frac{0.76\times 0.76\times 0.76+0.24\times 0.24\times 0.24}{0.76\times 0.76-0.76\times 0.24+0.24\times 0.24}$ is

The correct option is B 1
Formula used:
$a^3+b^3=(a+b)(a^2-ab+b^2)$
Now,
$\frac{0.76\times 0.76\times 0.76+0.24\times 0.24\times 0.24}{0.76\times 0.76-0.76\times 0.24+0.24\times 0.24}$= $\frac{(0.76{)}^3+(0.24{)}^3}{0.76\times 0.76-0.76\times 0.24+0.24\times 0.24}$

$=\frac{(0.76+0.24)(0.76\times 0.76-0.76\times 0.24+0.24\times 0.24)}{0.76\times 0.76-0.76\times 0.24+0.24\times 0.24}$

$=(0.76+0.24)=1$

Option B is correct.