The value of universal gravitational constant on earth for a particle of mass 5 kgs is

6.67 \times 10^{- 11}

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6.67 \times 10^{- 7}

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5 \times 6.67 \times 10^{- 11}

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6.67 \times 10^{- 23}

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Solution

The correct option is A $6.67 \times 10^{- 11}$
A universal gravitational constant is a constant number that does not depends on the masses of any planets or objects. And it is equal to $G = 6.67 \times 10^{- 11}$ $N m^{2} k g^{- 2}$
Option A

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Similar questions

Two spherical balls of mass 10 kg each are placed with their centers 10 cm apart. Find the gravitational force of attraction between them. Take $G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}$

Q. Why is the value of gravitational constant

6.67 \times 10^{- 11}

Q. Universal gravitational constant is given by

6.67 \times 10^{- 11} N m^{2} {k g}^{- 2}

. Then the no. of significant figures in it is:

Q. The value of universal gravitational constant G =

6.67 \times 10^{- 11} N m^{2} k g^{- 2}

. The value of G in units of

g^{- 1} c m^{3} s^{- 2}

Q. How is value of G determined as 6.67*10^-11_?

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The value of universal gravitational constant on earth for a particle of mass 5 kgs is

The correct option is A 6.67×10−11A universal gravitational constant is a constant number that does not depends on the masses of any planets or objects. And it is equal to G=6.67×10−11 Nm2kg−2Option A

The correct option is A $6.67 \times 10^{- 11}$
A universal gravitational constant is a constant number that does not depends on the masses of any planets or objects. And it is equal to $G = 6.67 \times 10^{- 11}$ $N m^{2} k g^{- 2}$
Option A