The vapour pressure of a dilute aqueous solution of glucose is 750 mm of Hg at 373 K. Calculate mole fraction of the solute :

0.013

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0.25

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0.968

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0.75

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Solution

The correct option is A $0.013$
$P^{o} = 760; P_{s} = 750 m m$
We know
$\frac{P^{o} - P_{s}}{P^{o}} = x_{2}$
$\Rightarrow \frac{760 - 750}{760} = x_{2}$

$\Rightarrow x_{2} = 0.013; x_{1} = 1 - 0.013 = 0.968$

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