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Liquids in Liquids

The vapour pr...

Question

The vapour pressure of a solvent decreased by $10 m m$ of mercury when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is $0.2$ . What should be the mole fraction of the solvent, if the decrease in the vapour pressure is to be $20 m m$ of mercury?

A

0.8

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B

0.6

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C

0.4

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D

0.2

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Solution

The correct option is D $0.6$
$Mole fraction of solute=lowering in vapour pressure vapour pressure of solvent$

comparing under the two conditions

$0.2mole fraction of solute=1020$

or, the mole fraction of solute $= 0.4$

mole fraction of solvent $= (1 - 0.4) = 0.6$

Hence, the correct option is $B$

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