{ The vapour pressure of }n -hexane at }350K is }840 torr }}{ and that of cyclohexane is }600 torr. Mole fraction of }}{ hexane in the mixture that boils at }350K and }1 atm }} pressure assuming ideal behaviour is

Q. At ${88}^{0}C$, benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at ${88}^{0}C$ at 1 atm pressure, benzene -toluene from an ideal solution?

Q. At ${88}^{0}C$ benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at ${88}^{0}C$ at 1 atm pressure?

Q. A certain liquid mixture of two liquids A and B (behaving ideally) has a vapour pressure 70 torr (1 torr=1 mm) at ${25}^{o}C$ for a certain mole fraction X of A. For the same mole fraction X for B in the mixture, the vapour pressure of mixture is 90 torr at ${25}^{o}C$. If $P_A^0-P_B^0=40$ torr, calculate $P_A^0,P_B^0$ and X :

Q. The molar enthalpy of vaporization of hexane $\left(C_6{H}_{14}\right)$ is $28.9kJ/mol$, and its normal boiling point is ${69}^{\circ }C$. What is the vapour pressure of hexane at ${25.00}^{\circ }C$ in $torr$? [$e^{-1.5}=0.222$]

Q. (a) The vapour pressure of n-hexane and n-heptane at $273K$ are $45.5mmHg$ and $11.4mmHg$, respectively.What is the composition of a solution of these two liquids if its vapour pressure at $273K$ is $37.3mmHg$.
(b) The mole fraction of n-hexane in the vapour above a solution of n-hexane and n-heptane is $0.75$ at $273K$.
What is the composition of the liquid solution?