The vapour pressure of water at 20 degree celsius is 17.54 mmHg. What will be the vapour pressure of the water in the apparatus shown after the piston is lowered, decreasing the volume of the gas above the liquid to one half of its initial volume (assume temperature constant).

A) 8.77 mmHg

B)17.54mmHg

C)35.08 mmHg

D) between 8.77 and 17.54mmHg

Q. The vapour pressure of water at ${20}^{o}C$ is $17.54mmHg$. Then the vapour pressure of the water in the apparatus is lowered, decreasing the volume of the gas above the liquid to one half of its initial volume (temp. constant) is:

Q. To what temperature must Indian gas sample be heated to double its pressure if the initial volume of gas at 75 degree celsius is decreased by 15%?

Q. The density of water is $1000$ kg per meter cube. The density of water vapour at $100$ degree Celsius and $1$ atmospheric pressure is $0.6$ kg per meter cube. The volume of a molecule multiplied by the total number gives what is called molecular volume. Estimate the ratio of the molecular volume to the total volume occupied by the water vapour under the above conditions of temperature and pressure.

Q. A vessel has nitrogen gas and water vapour in equilibrium with liquid water at a total pressure of $1$ atm. The partial pressure of water vapours is $0.3$ atm. The volume of this vessel is reduced to one-third of the original volume, at the same temperature, then find total pressure in atm of the system. (Neglect volume occupied by liquid water)

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If we decrease the pressure of the gas from $4.0atm$ to $1.0atm$ and decrease the temperature from $273$ degrees Celsius to $0$ degrees Celsius, what is the new volume of the gas?