The velocity-time graph of a particle in straight line motion is shown in figure. The particle starts its motion from origin.

The displacement of the particle from the origin after $8 s$ is

18 m

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16 m

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8 m

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6 m

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Solution

The correct option is D $6 m$
Displacement of particle = Area under the $v - t$ graph $= [(\frac{1}{2} \times 1 \times 4) + (2 \times 4) + (\frac{1}{2} \times 1 \times 4))] - [(\frac{1}{2} \times 1 \times 2) + (2 \times 2) + (\frac{1}{2} \times 1 \times 2)]$
$= 12 - 6 = 6 m$

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