The volume of a cubical box is 0.001331 $m^3$. Find the total surface area of the box.

Volume of cubical box = $0.001331m^3$

$a^3=0.001331$

$a=\sqrt[3]{30.001331}=0.11m$

Total surface area of the box = $6a^2$

$=6(0.11{)}^2$

$=6\times 0.0121$

$=0.0726m^2$