The water is filled upto height of $12\text{m}$ in a tank having vertical sidewalls. A hole is made in one of the walls at a depth ${}^{\prime }{h}^{\prime }$ below the waterlevel.The value of $h$ for which the emerging stream of waterstrikes the ground at the maximum range is $\text{(in m})$.

Q. A tank with vertical walls is mounted so that its base is at a height $H$ above the horizontal ground. The tank is filled with water to a depth '$h$' . A hole is punched in the side wall of the tank at a depth ' $x$ ' below the water surface. To have maximum range of the emerging stream,the value of $x$ is

Q. Water is filled upto height H units in a tank placed on the ground and whose side walls are vertical. A hole is made in one of the vertical wall such that the emerging stream of water strikes the ground at the maximum range. If the level in the tank is changing at the rate of R units per second, at that instant the rate at which range will be changing will be:

Q. A tank with vertical walls is mounted so that its base is at a height of $1.2m$ above the horizontal ground. The tank is filled with water to a depth $2.8m.$ A hole is punched in the side wall of thetank at a depth $xm$ below the surface of water to have maximum range of the emerging stream.Then the value of $x$ in meter is

Q. Water stands at a depth $H$ in a tank whose side wails are vertical. A hole is made on one of the walls at a depth $h$ below the water surface. Find at what distance from the foot of the wall does the emerging stream of water strike the floor?

Q. Water stands at a depth $H$ in a tank, whose side walls are vertical as shown in diagram. A hole is made on one of walls at a depth $h$ below water surface. Water comes out from the hole. The maximum range will be equal to :