The weight in grams of a non-volatile solute $(M.wt:60)$ to be dissolved in $90g$ of water to produce a relative lowering of the vapour pressure of $0.02$ is:

Q. $6g$ of non volatile solution is dissolved in $90g$ of water, such that the lowering in vapour pressure is $2\%$. The molecular weight of the solute is

Q. $12$g of a non-volatile solute dissolved in $108$g of water produces the relative lowering of the vapour pressure of $0.1$. The molecular mass of the solute is:

Q. Calculate the weight of non-volatile solute (in grams) having molecular weight $40\text{u}$, which should be dissolved in $57\text{g}$ octane to reduce its vapour pressure to $80\%$:

Q. One mole of non volatile solute is dissolved in two moles of water. The vapour pressure of the solution relative to that of water is