The weight of silver $(atomic wt. = 108)$ displaced by a quantity of electricity which displaces $5600 m L o f O_{2}$ at STP will be : -
(AIPMT-2014

54.0 g

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10.8 g

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108 g

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5.4 g

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Solution

The correct option is C $108 g$
According to Faraday's $2^{n d}$ law $\frac{w_{A g}}{E_{A g}} = \frac{w_{O_{2}}}{E_{O_{2}}}$ Weight of $O_{2} = n_{O_{2}} \times M_{O_{2}}$ Weight of $O_{2} = \frac{5600}{22400} \times 32$ Volume of $O_{2}$ at STP=22400mL $\frac{w_{A g}}{108} = \frac{(\frac{5600}{22400}) \times 32}{8}$ $∴ w_{A g} = 108 g$

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(atomic wt. = 108)

5600 m L o f O_{2}

= 108

O_{2}

O_{2}

O_{2}

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