The weight of the silver (atomic number: 108) displaced by a quantity of electricity which displaces 5600 ml of $O_2$ at STP will be:

The correct option is D $108.0g$

Solution:- (C) $108g$

No. of moles of $O_2$ displaced $=\frac{5600}{22400}=0.25\text{moles}$

Molecular weight of $O_2=32g$

Weight of $O_2=0.25\times 32=8g=1$ Equivalent of $O_2$

Now,

Equivalents of $Ag=$ Equivalents of $O_2$

Molecular weight of $Ag=108g$

Therefore,

Equivalents of $Ag=1$

$\therefore$ Weight of $Ag$ displaced $=\frac{108}{1}=108g$