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Question

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper limit of the highest class is


A
40
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B
15
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C
35
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D
25
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Solution

The correct option is C 35

If the width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10, then the upper limit of the highest class can be found as follows:
The upper limit of first class = 10+5=15
The upper limit of the fifth class=15 + 4 x 5 = 35.


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