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Question

The width of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. Find the upper class limit of the highest class.

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Solution

Given: Width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10.
Class width = Upper limit - lower limit
The upper limit of first class = 10 + 5 = 15
So the class intervals are:
10 - 15
15 - 20
20 - 25
25 - 30
30 - 35
The upper limit of the fifth class is 35.
(or)
The upper limit of the fifth class
= 15 + 4 x 5 = 35

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