There are 200 packets in a large box and each packet contains 3 electric devices in it- On testing- at the time of packing- it was noted that there are some faulty pieces in the packets- The data is as below - No of faulty devices in apacket amp- Less than24 amp- 24-36 amp- 36-48 amp- more than 48 amp- Total Batteries- Number of-batteries amp- 50 amp- 240 amp- 550 amp- 160 amp- 1000- - - - - - -i- If a buyer will only tolerate atthe -maximum -one faulty piece in a packet- what is the probability that a packet will be rejected- -ii- Another buyer will only take packets with all the -pieces functional- What is the probability that a packet will be rejected- - -4 MARKS- -

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Standard VIII

Mathematics

Probability

There are 200...

Question

There are 200 packets in a large box and each packet contains 3 electric devices in it. On testing, at the time of packing, it was noted that there are some faulty pieces in the packets. The data is as below

$\begin{matrix} N o o f f a u l t y d e v i c e s i n a p a c k e t & L e s s t h a n 24 & 24 - 36 & 36 - 48 & m o r e t h a n 48 & T o t a l B a t t e r i e s N u m b e r o f b a t t e r i e s & 50 & 240 & 550 & 160 & 1000 \end{matrix}$

(i) If a buyer will only tolerate atthe maximum one faulty piece in a packet, what is the probability that a packet will be rejected?
(ii) Another buyer will only take packets with all the pieces functional. What is the probability that a packet will be rejected? [4 MARKS]

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Solution

Concept: I Mark
Solution: 1.5 Marks each

Packets with more than one defective piece = 15 + 5 = 20
(i) Probability that the first buyer will reject a packet = 20/200 = 0.1
Packets with at least one piece that is defective = 15 + 5 + 25 = 45
(ii) Probability that the second buyer will reject a packet = 45/200 = 0.225

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