wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three blocks A, B and C are kept as shown in the figure. The coefficient of friction between A and B is 0.2, B and C is 0.1, C and between C and ground is 0.0. The masses of A, B and C are 3 kg, 2kg and 1 kg respectively, A is given a horizontal velocity 2 m/s. A, B and C always remain in contact. Find (in J) the magnitude of total work done by friction.

KfKi=Wfriction (K= Kinetic energy)


A

3 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

-3 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

6 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

-6 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

-3 J


Consider all the blocks as one system. As there is no external force in the horizontal direction,

P (momentum) = constant

Pi=3×2=6kgm/s

Let's assume the system moves with V after some time Pf=6×Vkgm/s

From conservation of linear momentum,

6V = 6

V = 1 m/s

Now we know work. Energy theorem,

KfKi=Wfriction

3×112×3×4=Wfriction

Wfriction=3J


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservative Forces and Potential Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon