Three blocks $A,B$ and $C$ of masses $1kg,2kg$ and $3kg$ respectively are arranged as shown in the figure. The coefficient of friction between different surfaces are shown in figure. A force of magnitude $20N$ acts on block $B$ in horizontal direction, find the acceleration of block $C$

The correct option is A Zero
Given: $m_A=1kg,m_B=2kg,m_C=3kg,{\mu }_A=0.5,{\mu }_B=0.4,{\mu }_C=0.3$
Let , ${\mu }_A$ be coefficient of friction between $A$ and $B$,
${\mu }_B$ be coefficient of friction between $B$ and $C$,
${\mu }_C$ be coefficient of friction between $C$ and ground
Let $f_A$ be friction between block $A$ and $B$,
$f_B$ be friction between block $B$ and $C$,
$f_C$ be friction between block $C$ and ground
$\left(f_B\right)max={\mu }_B{N}_B=0.4\times (1+2)\times 10=12N$
$\left(f_C\right)max={\mu }_C{N}_C=0.3\times (1+2+3)\times 10=18N$
As $\left(f_B\right)max<\left(f_C\right)max$
Hence, block $C$ will not move and have zero acceleration