Three cans contain 23.260 ml, 60.5 ml and 71.486 ml of kerosene. What should be the minimum capacity of a can that can hold the total quantity of kerosene?

150 ml

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170 ml

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160 ml

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155 ml

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Solution

The correct option is C 160 ml
All the units of measurement are same. After converting the numbers to like decimals, we can add all three quantities.

$23.260$
$+ 60.500$
$+ 71.486$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯$
$155.246 m l$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯$

155.246 will overflow in a 155 ml can. Hence, 160 ml is the minimum capacity of the can to hold the kerosene

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