Three identical dipoles are arranged as shown below. What will be the net electric field at P? $(K=\frac{1}{4\pi {ϵ}_0})$

Q. Three identical dipoles are arranged as shown below. what will be the net electric field at P $(k=\frac{1}{4\pi {\epsilon }_0})$

Q. Two identical electric dipoles are arranged on $x$-axis as shown in figure. Electric field at the origin will be ( Assume $\frac{1}{4\pi {ϵ}_0}=K$ )

Q. Two identical electric dipoles are arranged on $x$-axis as shown in figure. Electric field at the origin will be ( Assume $\frac{1}{4\pi {ϵ}_0}=K$ )

Q.

AT temperature T, a compound $A{B}_2\left(g\right)$ dissociates according to the reaction,
$2A{B}_{2\left(g\right)}\rightleftharpoons 2A{B}_{\left(g\right)}+B_{2\left(g\right)}$ with a degree of dissociation, x (where x << 1). If KP and P are equilibrium constant and equilibrium pressure respectively, the value of x is

Q. When three electric dipoles are near each other, they each experience the electric field of the other two, and the three dipole system has a certain potential energy. Figure below shows three arrangements $\left(1\right),\left(2\right)$ and $\left(3\right)$ in which three electric dipoles are side by side. All three dipoles have the same magnitude of electric dipoles have the same magnitude of electric dipole moment, and the spacings between adjacent dipoles are identical. If $U_1$, $U_2$ and $U_3$ are potential energies of the arrangements $\left(1\right),\left(2\right)$ and $\left(3\right)$ respectively then-