Three pipes A,B and C can fill a tank in 6 hours After working at it together for 2 hours , C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is :
A
10
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B
12
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C
14
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D
16
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Solution
The correct option is C14 Part of the tank filled by (A + B + C) in 2 hours = 2×16=13 Remaining part = 1−13=23 ∴23rd of the tank is filled by (A + B) in 7 hours. ∴ The whole tank is filled by (A + B) in (7×32)hours=212hours ∴ Part of the tank filled by C in 1 hour = Part of the tank filled by (A + B + C) in 1 hour - Part of the tank filled by (A + B) in 1 hour = 16−221=342=114 ∴ C can fill the whole tank in 14 hours.