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How many cubes of 10 cm edge can be put in a cubical box of 1 m edge?
(a) 10
(b) 100
(c) 1000
(d) 10000

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Solution

(c) 1000

Volume of the smaller cube $= (10 c m)^{3} = 1000 c m^{3}$
Volume of box $= (100 c m)^{3} = 1000000 c m^{3}$ [1 m = 100 cm]
∴ Total no. of cubes $= \frac{100 \times 100 \times 100}{10 \times 10 \times 10} = 1000$

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