Two balls $A$ and $B$ of the same size are dropped from the same point under gravity. If the air resistance acting on both the balls is same and the mass of $A$ is greater than the mass of $B$ , then

The ball A reaches earlier.

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The ball B reaches earlier.

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Both the balls reach the ground simultaneously.

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Cannot say, as the data is insufficient.

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Solution

The correct option is A $The ball A reaches earlier.$
Let the air resistance force acting on the balls be $F$

From the figure acceleration of the ball is given by
$a = \frac{m g - F}{m} = g - \frac{F}{m}$
$∵ m_{A} > m_{B}$
$\Rightarrow a_{A} > a_{B}$
Hence, ball $A$ will reach the ground earlier.

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Two balls A and B of the same size are dropped from the same point under gravity. If the air resistance acting on both the balls is same and the mass of A is greater than the mass of B, then

The correct option is A The ball A reaches earlier.Let the air resistance force acting on the balls be F From the figure acceleration of the ball is given by a=mg−Fm=g−Fm ∵ mA>mB ⇒ aA>aB Hence, ball A will reach the ground earlier.

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