Two bodies of masses nbsp- - m - 1- nbsp- and nbsp- nbsp- m - 2- nbsp- nbsp- have same nbsp-kinetic energy- The ratio of their momentum is nbsp- - m - 2 - m - 1 - - m - 1 - m - 2 - m - 1 - 2 - m - 2 - 2- m - 2 - 2 - m - 1 - 2-

The correct option is B √( m _ 1 / m _ 2 ) Let p_1 be the momentum of body of mass m_1 and #160; p_2 be the momentum of body of mass ...

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Standard X

Physics

Kinetic Energy

Two bodies of...

Question

Two bodies of masses $m_{1}$ and $m_{2}$ have same kinetic energy. The ratio of their momentum is

\sqrt{\frac{m_{2}}{m_{1}}}

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\sqrt{\frac{m_{1}}{m_{2}}}

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\frac{m_{1}^{2}}{m_{2}^{2}}

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\frac{m_{2}^{2}}{m_{1}^{2}}

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Solution

The correct option is B $\sqrt{\frac{m_{1}}{m_{2}}}$
Let $p_{1}$ be the momentum of body of mass $m_{1}$
and $p_{2}$ be the momentum of body of mass $m_{2}$

Given that both masses have same kinetic energy

$⟹ \frac{p_{1}^{2}}{2 m_{1}} = \frac{p_{2}^{2}}{2 m_{2}}$

$⟹ (\frac{p_{1}}{p_{2}})^{2} = \frac{m_{1}}{m_{2}}$

$⟹ \frac{p_{1}}{p_{2}} = \sqrt{\frac{m_{1}}{m_{2}}}$ ........... Required Answer

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Two bodies of masses m1 and m2 have same kinetic energy. The ratio of their momentum is

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