Two bullets are fired with horizontal velocity of 50 M per second 100 M per second from 2 Guns at a height of 19.6 m. a) will Bullet strike the ground. b) if yes then after how much time and which Bullet will strike first .c) what would be the part of the bullet?( g= 9.8 m/s^2₎

yes surely.because the gravity will pull the bullets towards ground and they will hit the ground.
consider the vertical motion of the bullets.both of them have zero velocities in vertical direction(although they have velocities in horizontal direction).
lets take the downward direction as positive
initial velocity in vertical direction=0
acceleration in vertical direction=g=+9.8 m/s^2
so to hit the ground the bullets has to travel a distance of 19.6m from its initial height.
so according to the equation
s=ut+1/2at^2
19.6=0t+1/2gt^2
19.6=1/2*9.8*t^2
t^2=4
so t=2 second
this is the time when both the bullets hit the ground.
They will hit the ground at same time because their initial vertical velocity and initial height were same.but they will hit the ground at different places because each bullet having different velocities will travel different distances in the horizontal direction.
the one with 50m/s horizontal velocity will hit the ground at 50*2=100metres
and the one with 100 m/s velocity will hit the ground at 100*2=200 metres
(multiplied by 2 because that is the time they can travel,as after 2 seconds they will hit the ground)
i really dont understand what you have asked in the c part
THANKS