wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two containers A and B contain ideal gases, helium and oxygen respectively. Volume of both containers are equal, and pressure is also equal. Container A has twice the number of molecules than container B. If VA and VB represent the rms speed of gases in containers A and B respectively, then

A
VAVB=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
VAVB=4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
VAVB=2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
VAVB=8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C VAVB=2
As we know that the ideal gas is given by : PV=nRT

For A:PV=2nRTA(1)
For B:PV=nRTB(2)

Given that pressure and volume are same therefore,
from equations (1) and (2)khj
TB=2TA

RMS speed of gas is given by :

Vrms=3RTM

VAVB=3RTA43RTB32

VAVB=3RTA43RTA32=2

VAVB=2




flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Using KTG
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon