Two guns - A- and - B- can fire bullets at speeds - 1 km-s- and - 2 km-s- respectively- From a point nbsp-on a horizontal ground- they are fired in all nbsp-possible directions- The ratio of maximum areas nbsp-covered by the bullets fired by the two guns-on the ground is- 1 - 4- 1 - 2- 1 - 8- 1 - 16-

The correct option is D 1 : 16 R = u^2sin 2θg A = π R^2 A∝ R^2 A∝ u^4 A_1A_2 = u_1^4u_2^4 = [12 ]^4 = 116 . ...

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Standard XII

Physics

Work Energy Theorem Application

Two guns ...

Question

Two guns $A$ and $B$ can fire bullets at speeds $1 k m / s$ and $2 k m / s$ respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets fired by the two guns,on the ground is

1 : 2

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1 : 4

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1 : 8

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1 : 16

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Solution

The correct option is D $1 : 16$
$R = \frac{u^{2} sin 2 θ}{g}$
$A = π R^{2}$
$A \propto R^{2}$
$A \propto u^{4}$
$\frac{A_{1}}{A_{2}} = \frac{u_{1}^{4}}{u_{2}^{4}} = {[\frac{1}{2}]}^{4} = \frac{1}{16}$ .

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Two guns A and B can fire bullets at speeds 1 km/s and 2 km/s respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets fired by the two guns,on the ground is

The correct option is D 1:16R=u2sin2θgA=πR2A∝R2A∝u4A1A2=u41u42=[12]4=116.

Two guns $A$ and $B$ can fire bullets at speeds $1 k m / s$ and $2 k m / s$ respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets fired by the two guns,on the ground is

The correct option is D $1 : 16$
$R = \frac{u^{2} sin 2 θ}{g}$
$A = π R^{2}$
$A \propto R^{2}$
$A \propto u^{4}$
$\frac{A_{1}}{A_{2}} = \frac{u_{1}^{4}}{u_{2}^{4}} = {[\frac{1}{2}]}^{4} = \frac{1}{16}$ .