Two objects of mass 1.5 kg are moving in same straight line but in opposite direction. The velocity of each object is 2.5 m/s before collision during which they stick together. What will be their combined velocity after collision

2.5 m/s

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5 m/s

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6.25 m/s

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Solution

The correct option is D 0
$m_{1} v_{1} = 1.5 \times 2.5 = 3.75 k g m / s, m_{2} v_{2} = - 3.75 k g m / s$
momentum after collision, $M V = m_{1} v_{1} + m_{2} v_{2} = 0$
$∴ v e l o c i t y = 0$

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Two objects of mass 1.5 kg are moving in same straight line but in opposite direction. The velocity of each object is 2.5 m/s before collision during which they stick together. What will be their combined velocity after collision

The correct option is D 0m1v1=1.5×2.5=3.75kgm/s,m2v2=−3.75kgm/smomentum after collision, MV=m1v1+m2v2=0∴velocity=0

The correct option is D 0
$m_{1} v_{1} = 1.5 \times 2.5 = 3.75 k g m / s, m_{2} v_{2} = - 3.75 k g m / s$
momentum after collision, $M V = m_{1} v_{1} + m_{2} v_{2} = 0$
$∴ v e l o c i t y = 0$