Two ores $A$ and $B$ were taken. On heating ore $A$ gives $C O_{2}$ whereas, ore $B$ gives $S O_{2}$ . What steps will you take to convert them into metals?

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Solution

Calcination is the process of turning ore into an oxide by exposing it to high temperatures.
Carbon dioxide ( $C O_{2}$ ) is produced when a Carbonate ( $C {O_{3}}^{2 -}$ ) ore is heated. To obtain metal oxide, a carbonate ore is calcinated.
Calcination of Zinc carbonate ( $Z n C O_{3}$ ) is shown in the equation below.
$\underset{z i n c c a r b o n a t e}{Z n C O_{3} (s)} \to \underset{z i n c o x i d e}{Z n O (s)} + \underset{c a r b o n d i o x i d e}{C O_{2} (g)}$
Sulphur dioxide ( $S O_{2}$ ) is produced when a sulphide ( $S^{2 -}$ ) ore is roasted. Zinc oxide ( $Z n O$ ) is made by roasting Zinc sulphide ( $Z n S$ ).
Roasting is the process of heating ore to a temperature below its melting point while in the presence of air or Oxygen.
Roasting of Zinc sulphide ( $Z n S$ ) is shown in the equation below.
$\underset{z i n c s u l p h i d e}{2 Z n S (s)} + \underset{o x y g e n}{3 O_{2} (g)} \to \underset{z i n c o x i d e}{2 Z n O (s)} + \underset{s u l p h u r d i o x i d e}{2 S O_{2} (g)}$
Reduction roasting is the process of removing Oxygen ( $O_{2}$ ) from a component of an ore by using Carbon monoxide ( $C O$ ).
Now, we use reduction to convert Zinc oxide ( $Z n O$ ) into pure Zinc ( $Z n$ ).
$\underset{z i n c o x i d e}{Z n O (s)} + \underset{c a r b o n}{C (s)} \to \underset{z i n c}{Z n (s)} + \underset{c a r b o n m o n o x i d e}{C O (g)}$

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Two ores A and B were taken. On heating ore A gives CO2 whereas, ore B gives SO2. What steps will you take to convert them into metals?

Two ores $A$ and $B$ were taken. On heating ore $A$ gives $C O_{2}$ whereas, ore $B$ gives $S O_{2}$ . What steps will you take to convert them into metals?