two parallel plates have charges Q1 and Q2 on them and the capaci†an ce is C. the potential difference between them i

Q. Two parallel plates have charges $Q_1$ and $Q_2$ on them and the capacitance is c. The potential difference between them is

Q. Two identical metal plates are given positive charge $Q_1$ and $Q_2$ $(<Q_1)$ respectively. If they are now brought close together to form a parallel plate capacitor with capacitance $C$, the potential difference between them is

Q. In an isolated parallel plate capacitor of capacitance $C$, the four surfaces have charges $Q_1,Q_2,Q_3$ and $Q_4$ as shown. The potential difference between the plates is:

Q. Two conducting plates A and B are placed parallel to each other at a small distance between them. Plate A is given a charge $q_1$ and plate B is given a charge $q_2$. Then :

Q. The potential difference between two parallel plates 1 cm apart is 100V. The electric field strength between them is :