Two particles A and B are shot from the same height at $t=0$ in opposite directions with horizontal velocities $3m/s$ and $4m/s$ respectively. If they are subjected to the same vertical acceleration due to gravity ($g=9.8m/s^2$). the distance between them when their velocity vectors become mutually perpendicular is:

Q. Two particles move in a uniform gravitational field with an acceleration $g$. At the initial moment the particles were located over a tower at one point and moved with velocities $v_1=3m/s$ and $v_2=4m/s$ horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular, rounded off up to one decimal place will be: ( Take $g=9.8m{s}^{-2}$)

Q. Two particle move in a uniform gravitational field with an acceleration $g$. At the initial moment the particles were located over a tower at one point and moved with velocities $v_1=3m/s$ and $v_2=4m/s$ horizontally opposite directions. Find the distance between the particles at the moment when their velocity vectors become mutually perpendicular.

Q. Two particles at $t=0$ are thrown horizontally in opposite directions from the same point from a height $h$ with velocities $4m{s}^{-1}$ and $3m{s}^{-1}$. Find the time when their velocities are perpendicular.

Q. Two particles move in a uniform gravitational field with an acceleration $g$. At the initial moment the particles were located at one point and move with velocities $v_1=3.0m/s$ and $v_2=4.0m/s$ horizontally in opposite directions. Find the distance between the particles at the moment when their velocity vectors become mutually perpendicular.

Q. Two particles are projected from the top of a tower with velocities $10\text{m/s}$ and $80\text{m/s}$ in horizontal but in opposite directions. After what time $t$ their velocity vectors will be mutually perpendicular to each other? (Take $g=10{\text{m/s}}^2$)