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Question

Two particles A and B of masses m and 2m are suspended from two massless springs of force constants K1 and K2. During their oscillation, if their maximum velocities are equal, then ratio of amplitudes of A and B is :

A
K1K2
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B
K22K1
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C
K2K1
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D
2K1K2
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Solution

The correct option is A K22K1
Since by energy conservation,

12KA2=12Mv2max.

Hence, K1A21K2A22=m2m=12, since maximum velocities are same in both cases.

Hence, A1A2=K22K1.



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