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Question
Two plane mirror A and B are oriented perpendicular to each other. A light ray incident at angle θ on mirror A is also reflected by the mirror B. If the reflected ray from mirror B is parallel to the incident ray on A, such that the ray reflected from the first mirror as the same angle of incidence on the second mirror then find the value of θ.
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Solution
It is given i1=i2And from figure i2=90−θAnd from laws of reflection r1=i1=90−θHence x=90−r1=θAnd since i2=i1=90−θHence y=90−i2=θso from triangle900+x+y=18002θ=900θ=450
It is given i1=i2
And from figure i2=90−θ
And from laws of reflection r1=i1=90−θ
Hence x=90−r1=θ
And since i2=i1=90−θ
Hence y=90−i2=θ
so from triangle
900+x+y=1800
2θ=900
θ=450
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