Two plane mirror are inclined to each other such that a ray of light incident on the first mirror $(M_{1})$ and parallel to the second mirror $(M_{2})$ is finally reflected form th second mirror $(M_{2})$ parallel to the first mirror $(M_{1})$ the angle between the two mirrors will be :

60^{0}

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75^{0}

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90^{0}

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45^{0}

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Solution

The correct option is A $60^{0}$
$\begin{matrix} Assuming angles between two mirrors be θ . we know that angle made by light ray for incidence and reflection with mirror 95 Same. Now by geometry \begin{matrix} Sum of angles in a triangle = 180^{\circ} 30 = 180^{\circ} θ = 60^{\circ} \end{matrix} \end{matrix}$

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Similar questions

Q. Two plane mirrors are inclined to each other such that a ray of light incident on the first mirror

(M_{1})

and parallel to the second mirror

(M_{2})

is finally reflected from the second mirror

(M_{2})

parallel to the first mirror

(M_{1})

. The angle between the two mirrors will be :

The plane mirrors $M_{1}$ and $M_{2}$ are inclined to each other such that a ray of light incident on mirror $M_{1}$ and parallel to the mirror $M_{2}$ is reflected from mirror $M_{2}$ parallel to the mirror $M_{1}$ . The angle between the two mirror is (in degrees)