Two planes mirrors are inclined at an $\angle \theta$, find $\theta$ if the incident ray is parallel to mirror $M_1$?

Q. Two plane mirrors $M_1$ and $M_2$ are inclined to each other at ${70}^{\circ }.$ A ray incident on the mirror $M_1$ at an angle $\theta$ falls on $M_2$ and is then reflected parallel to M, for

Q. Two plane mirrors are inclined at ${70}^0$. A ray incident on one mirror at an angle $\theta$ after reflection falls on the second mirror and is reflected from there parallel to the first mirror $\theta$ is

Q. Two plane mirrors are inclined at ${70}^{\circ }.$ A ray incident on one mirror at incidence angle $\theta$ , after reflection falls on the second mirror and is reflected from there parallel to the first mirror. The value of $\theta$ is

Q. Two plane mirror A and B are inclined at angle $\theta (<{90}^o)$ to each other. A light ray parallel to mirror B is incident on mirror A and it becomes parallel to mirror A after reflection from mirror B. Find the value of angle $\theta$.

Q. Two plane mirrors are inclined at angle $\theta$. An optical ray $AB$ is incident on a mirror at an angle $2\theta$ with the mirror, as shown. The reflected ray from the second mirror, $CD$ is perpendicular to the incident ray. Find angle $q$-