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Question

Two soap bubbles of different radii RA and RB(<RA) coalesces to form an interface of radii R. The correct relation of R with RA and RB is


A
R=RARB
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B
R=RA+RB2
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C
1R=1RB1RA
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D
1R=1RA+1RB
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Solution

The correct option is C 1R=1RB1RA
We know excess pressure in soap bubble is
Δp=4TR
p2p1=4TR ...(1)

According to question


For Bubble A, pApo=4TRA pA=4TRA+po ...(2)

For Bubble B, pBpo=4TRB pB=4TRB+po ...(3)
For Interface, pBpA=4TR
4TRB4TRA=4TR
1R=1RB1RA

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