Two trains are running in the same directions at the speed of 60 km/hr and 96 km/hr. If the faster train passes a man in the slower train in 20 seconds, then the length of the faster train is
A
100 m
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B
125 m
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C
150 m
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D
200 m
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Solution
The correct option is D200 m Relative speed = (96−60) km/hr = 36 km/hr =(36×518) m/s = 10 m/sec As we know D = s x t ∴ Length of faster train = 10×20 = 200 m