Two trains of equal length are running on parallel lines in the same direction at 46 kmph and 36 kmph. The faster train passes the slower train in 36 seconds. The length of each train is:

50 m

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72 m

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80 m

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82 m

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75 m

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Solution

The correct option is A
50 m

Let the length of each train be `x' metres.

Then, distance covered = 2x metres.

Related speed = (46 - 36) km/hr = $(10 \times \frac{5}{18})$ m/sec = $(\frac{25}{9})$ m/sec

$∴$ $\frac{2 x}{36} = \frac{25}{9} \Leftrightarrow 2 x = 100 \Leftrightarrow x = 50.$

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Two trains of equal length are running on parallel lines in the same direction at 46 kmph and 36 kmph. The faster train passes the slower train in 36 seconds. The length of each train is:

The correct option is A 50 m Let the length of each train be `x' metres. Then, distance covered = 2x metres. Related speed = (46 - 36) km/hr = (10×518)m/sec =(259)m/sec ∴2x36=259⇔2x=100⇔x=50.

The correct option is A
50 m

Let the length of each train be `x' metres.

Then, distance covered = 2x metres.

Related speed = (46 - 36) km/hr = $(10 \times \frac{5}{18})$ m/sec = $(\frac{25}{9})$ m/sec

$∴$ $\frac{2 x}{36} = \frac{25}{9} \Leftrightarrow 2 x = 100 \Leftrightarrow x = 50.$