Two uniform rods of equal length but different masses are rigidly joined to form an $L$ shaped body, which is then smoothly pivoted about $O$ as shown. If the body is in equilibrium in the shown configuration, ratio $M:m$ will be :

Q. Two uniform rods of equal length but different masses are rigidly joined to form an L-shaped body, which is then pivoted about O as shown in the figure. If the system is in equilibrium in the shown configuration. Then the ratio M/m will be:

Q. Two uniform rods of equal lengths but different masses are rigidly joined to form an $L-$shaped body, which is then pivoted as shown. If in equilibrium the body is in shown configuration, ratio $M/m$ will be $\sqrt{x}$. The value of $x$ is

Q. Two uniform rods of equal length but different masses are rigidly joined to form an $L$ - shaped body which is pivoted about point $\text{O}$ as shown. If in the shown configuration, the body is in equillibrium, the ratio $M/m$ will be.

Q. Two uniform rods of equal length but different masses are rigidly joined to form an $L$ - shaped body which is pivoted about point $\text{O}$ as shown. If in the shown configuration, the body is in equillibrium, the ratio $M/m$ will be.

Q. Two uniform rods of equal length but of different masses are rigidly combined to form a $L-$ shaped body, which is then pivoted about $O$ as shown in figure. If combination is in equilibrium then ratio $M/m$ will be