Urea is a very important nitrogenous fertilizer. Its formula is $C O N_{2} H_{4}$ Calculate the percentage of nitrogen in urea (C = 12, O = 16, N = 14 and H = 1).

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Solution

Urea has the formula $N H_{2} - C O - N H_{2}$ , i.e. $C O N_{2} H_{4}$
Molecular mass of urea = 60 g/mol

Atomic mass of N = 14 & number of atoms = 2
i.e. 28 g/mol of urea

Thus the % of nitrogen = $\frac{28}{60} \times 100 = 46.66 %$

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