Simplify the below expression and express it in exponential form of its prime factors.
$\frac{{10}^6\times 9^2}{6^4}$

The correct option is C $2^2$\times5^6$
Given expression is:
$\frac{{10}^6\times 9^2}{6^4}$

$=\frac{(2\times 5{)}^6\times (3^2{)}^2}{(2\times 3{)}^4}$

$=\frac{2^6\times 5^6\times (3^2{)}^2}{2^4\times 3^4}$ $(\because [a\times b{]}^m=a^m\times b^m)$

$=\frac{2^6\times 5^6\times 3^4}{2^4\times 3^4}$ $(\because [a^m{]}^n=a^{m\times n})$

$=2^{6-4}\times 5^6\times 3^{4-4}$ $(\because \frac{a^m}{a^n}=a^{m-n})$

$=2^2\times 5^6$