Vapour density of a gas is 11.2 . The volume occupied by 11.2 g of this gas at STP is:

22.4 l

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11.2 l

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1 l

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2.25 l

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Solution

The correct option is B $11.2 l$
$V a p o u r d e n s i t y = \frac{m o l e c u l a r w e i g h t}{2}$
$∴$ Molecular weight is $22.4 g / m o l e$ .
At STP, volume occupied by 1 mole of gas is $22.4 l$ and therefore, volume occupied by 0.5 moles (11.2 g) of gas will be $11.2 l$ .

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