Vector A is of length 2 cm and is 60- above the x-axis in the first quadrant- Vector B is of length 2 cm and 60- below the x-axis in the fourth quadrant- The sum A-B- is a vector of magnitude cm -A- 2 along - y-axisB- 2 along -x-axisC- 1 along - x-axisD- 2 along -x-axis

Let us assume, R = A + B = (A cos60 î + Asin60 ĵ) + (Bcos60 î Bsin 60 ĵ) ∵ |A| = |B| = 2 cm So, R = (A cos 60 + B cos60)î = 2î Hence 2 cm along + x axis ...

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Byju's Answer

Standard XII

Physics

Addition and Subtraction in Unit Vector Notation

Vector A is o...

Question

Vector $\to A$ is of length 2 cm and is $60^{\circ}$ above the x -axis in the first quadrant. Vector $\to B$ is of length 2 cm and $60^{\circ}$ below the x-axis in the fourth quadrant. The sum $\to A + \to B$ is a vector of magnitude (cm).

2 along +y-axis

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2 along +x-axis

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1 along -x-axis

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2 along -x-axis

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Solution

The correct option is B 2 along +x-axis
Let us assume,
$\to R = \to A + \to B$
$= (A cos 60^i + A sin 60^j) + (B cos 60^i - B sin 60^j)$
$∵ | \to A | = | \to B | = 2 c m$
So, $R = (A cos 60 + B cos 60)^i = 2^i$
Hence $2 c m$ along + x -axis

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