Vector $\overrightarrow{A}$ is of length 2 cm and is ${60}^{\circ }$ above the x -axis in the first quadrant. Vector $\overrightarrow{B}$ is of length 2 cm and ${60}^{\circ }$ below the x-axis in the fourth quadrant. The sum $\overrightarrow{A}+\overrightarrow{B}$ is a vector of magnitude (cm).

Q. Vector $\overrightarrow{A}$ is of length 2 cm and is inclined at ${60}^{\circ }$ above the x -axis in the first quadrant. Vector $\overrightarrow{B}$ is of length 2 cm and inclined at ${60}^{\circ }$ below the x-axis in the fourth quadrant. The difference $\overrightarrow{A}-\overrightarrow{B}$ is a vector of magnitude (cm)

Q. Vector $\overrightarrow{A}$ is $2cm$ long and is ${60}^o$ above the x-axis in the first quadrant. Vector $\overrightarrow{B}$ is $2cm$ long and is ${60}^o$ below the x-axis in the fourth quadrant. The sum $\overrightarrow{A}+\overrightarrow{B}$ is a vector of magnitude

Q. Vector $\overrightarrow{A}$ is of length 2 cm and is ${60}^{\circ }$ above the x -axis in the first quadrant. Vector $\overrightarrow{B}$ is of length 2 cm and ${60}^{\circ }$ below the x-axis in the fourth quadrant. The sum $\overrightarrow{A}+\overrightarrow{B}$ is a vector of magnitude (cm).

Q. Vector $\overrightarrow{A}$ is of length $2\text{cm}$ and makes an angle ${60}^{\circ }$ with the $x$ -axis in the first quadrant. Vector $\overrightarrow{B}$ is of length $2\text{cm}$ and ${60}^{\circ }$ below the $x$-axis in the fourth quadrant. The sum $\overrightarrow{A}+\overrightarrow{B}$ is a vector of magnitude in $\text{cm}$.

Q. Vector $\overrightarrow{A}$ is of length $2\text{cm}$ and is inclined at ${60}^{\circ }$ above the $x-$axis in the first quadrant. Vector $\overrightarrow{B}$ is of length $2\text{cm}$ and inclined at ${60}^{\circ }$ below the $x-$axis in the fourth quadrant. Then $(\overrightarrow{A}-\overrightarrow{B})$ is a vector of magnitude