Volume occupied by 1 molecule of water (density = 1 g/cm³)?

$$\begin{gathered} Noofmole=\frac{Noofmolecules}{Avogadronumberofmolecules} \\ =\frac{1}{6.022\times {10}^{23}} \\ Givenmass=Mole\times molarmass \\ =\frac{1}{6.022\times {10}^{23}}\times 18=2.989\times {10}^{-23}g \\ Density=\frac{Mass}{Volume} \\ Volume=\frac{Mass}{density}=\frac{2.989\times {10}^{-23}}{1}=2.989\times {10}^{-23}c{m}^3 \end{gathered}$$