What are the corresponding anhydrides of the following oxyacids- HClO - 4- -160- -160- HClO - 3- -160- -160- HClO - 2- and -160- -160- HOCl- HClO - 4 - Cl - 2 O - 3- HClO - 3 - Cl - 2 O - 6- HClO - 2 - Cl O- 2- HOCl - Cl - 2 O-4-

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Solving Equations with Variables on Both Sides

What are the ...

Question

What are the corresponding anhydrides of the following oxyacids:
${H C l O}_{4}$ , ${H C l O}_{3}$ , ${H C l O}_{2}$ and $H O C l$ .

{H C l O}_{4} : {C l}_{2} O_{3}

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{H C l O}_{3} : {C l}_{2} O_{6}

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{H C l O}_{2} : C l O_{2}

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H O C l : {C l}_{2} O_{4}

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Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H O C l, H C l O_{2}, H C l O_{3}

H C l O_{4}

H O C l, H C l O_{2}, H C l O_{3}

H C l O_{4}

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